Math, asked by samarthmaheshwari04, 8 months ago

sec4θ-sec2θ=tan4θ+tan2θ

Answers

Answered by amourya13
3

Step-by-step explanation:

sec4θ-sec2θ=tan4θ+tan2θ

tan4θ+tan2θ= tan^2θ (tan^2θ + 1 )

(sec^2θ-1)(sec2θ) = [ tan^2θ + 1= sec^2θ) =

sec4θ-sec2θ

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