sec⁴ Theta-Sec²Theta =Tan⁴ Theta +Tan² Theta .Prove the.
Answers
Answered by
2
Step-by-step explanation:
Given,
sec⁴ θ – sec²θ = tan⁴θ + tan²θ
L.H.S
= sec⁴ θ – sec²θ
= sec² θ (sec² θ -1)
= (1 + tan² θ) (1 + tan² θ -1) …..[ sec² θ = 1 + tan² θ ]
= (1 + tan² θ) ( tan² θ)
= tan²θ + tan⁴θ
L.H.S = R.H.S
I hope you got the answer ....
Answered by
0
Answer:
Thus is your required proof.
Attachments:
Similar questions