sec4A - cos4A = 1- Cos2A
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Answer:
Correct question is ---> sin⁴A - cos⁴A = 1 - 2cos²A
LHS = sin⁴A - cos⁴A
= (sin²A - cos²A)(sin²A + cos²A)
As you know, sin²x + cos²x = 1
So, sin²A + cos²A = 1
∴ LHS = (sin²A - cos²A) × 1
= (1 - cos²A - cos²A) [ sin²x = 1 - cos²x from identities ]
= 1 - 2cos²A = RHS
[Hence, proved]
Step-by-step explanation:
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