sec4A= cosec(A-20)find A
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hence angle are equal then
4A+A-20=90
5A=110
A=22°
4A+A-20=90
5A=110
A=22°
HappiestWriter012:
please explain which property was used
Answered by
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sec4A = cosec(A-20)
sec 90 - ( 90 - 4A) = cosec(A-20)
cosec(90-4A) = cosec( A - 20)
90-4A = A - 20
90 + 20 = 5A
5A = 110
A = 110/5 = 22 .
Therefore , A = 22°
Hope helped!
sec 90 - ( 90 - 4A) = cosec(A-20)
cosec(90-4A) = cosec( A - 20)
90-4A = A - 20
90 + 20 = 5A
5A = 110
A = 110/5 = 22 .
Therefore , A = 22°
Hope helped!
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