Question

sec4a-sec2a=2

find general solution

for 30 points

Answer 1

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sec4A - sec2A =2

1/cos4A - 1/cos2A =2

cos2A+ cos4A =2 cos4A * cos2A

cos2A + cos4A = cos6A + cos2A [cosC + cosD= 2 cos(C+D)/2 * cos(C-D)/2 ]

cos6A - cos4A = 0

2 sin(6A +4A)/2 sin(4A- 6A) =0

sin5A sin2A =0

so sin5A =0 & sin2A =0

or 5A = 0 & 2A = 0 =0

so A=npi/5& A=npi/2 where n =z [ A = 0 ]

Answer 2

Step-by-step explanation:

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