Question

sec⁴A-sec²A is equal to​

Answer 1

Answer:

Sec⁴A-sec²A=tan⁴A+tan²A.

Answer 2

Step-by-step explanation:

$\sec ^{4} A - sec ^{2} A \\ \\ sec ^{2} A(sec ^{2} A - 1) \\ \\ sec ^{2} A(1 + tan ^{2} A - 1) \\ \\ (sec ^{2} A)(tan ^{2} A )$

REQUIRED ANS..