sec⁴A- sec²A is equal to
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Answer:
sec⁴A- sec²A is equal to
Step-by-step explanation:
=
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Solution:- sec⁴A - sec²A
- ⟹ sec²A ( sec²A - 1)
⟹ sec²A (tan²A) [∵sec²A -1 = tan²A]
we know that , sec²A = 1/cos²A and tan²A = sin²A/cos²A
∴ 1/cos²A × sin²A/cos²A
⟹ sin²A/cos⁴A
Hence , sec⁴A -sec²A = sec²A(tan²A) = sin²A/cos⁴A
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