Math, asked by mithleshkumarvfx, 7 months ago

Sec4A-sec2A= tan2A+Tan4A

Answers

Answered by varshagawande63389

3

Answer:

I explain step by step

Step-by-step explanation:

tan2A+tan4A

tan2A(1-tan2A)

(sec2A-1)(1+tan2A).(1+tan2A=sec2A)

(sec2A-1sec2A)

sec4A-sec2A

I hope helpful for you

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