sec4A - sec2A = tan4A + tan2A
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tan²A+tan⁴A
tan²A(1+tan²A)
(sec²A-1)(1+tan²A). (1+tan²A=sec²A)
(sec²A-1)sec²A
sec⁴A-sec²A
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Answer:
sec2A=tan6A
Step-by-step explanation:
this is the right answer.
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