Math, asked by subhoberh2004, 9 months ago

sec⁴A-sec²A=tan⁴A+tan²A
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Answers

Answered by TajDutta

1

Step-by-step explanation:

LHS

sec⁴A-sec²A

sec²A(sec²A-1)

sec²A*tan²A

RHS

tan⁴A+tan²A

tan²A(tan²A+1)

tan²A*sec²A........ =LHS

Hence proved

hope it is what you are looking for ʘ‿ʘ

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