sec500 .sin400+cos400 .cosec500
Answers
Answered by
2
Answer:
To evaluate,
sec50
0
sin40
0
+cos40
0
csc50
0
We know that,
secθ=
cosθ
1
, cscθ=
sinθ
1
∴sec50
0
sin40
0
+cos40
0
csc50
0
=
cos50
0
sin40
0
+
sin50
0
cos40
0
We have sin(90
0
−θ)=cosθ
sin(40
0
)=sin(90
0
−50
0
)=cos(50
0
)
sin(50
0
)=sin(90
0
−40
0
)=cos(40
0
)
Therefore,
=
cos50
0
sin40
0
+
sin50
0
cos40
0
=
cos50
0
cos50
0
+
cos40
0
cos40
0
=1+1
=2
Answered by
2
sec500sin 400 +cos400 cosec500 sec(90-40)0 sin400 +cos(90-50)0 cosec 500 cosec400 sin400 +sin500 cosec500 =1+1=2 [cosec0 x sin 0=1]
hope it helps you
Similar questions