Math, asked by sandip19, 1 year ago

sec6A-tan6A=1+3tan2A+3tan4A

Answers

Answered by DEvvv94

6

sec6A-tan6A=1+3tan2A+3tan4A
-1=1+3(tan2A+tan4A)
-2=3(tan6A)
-2/3=tan6A

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