Question

sec⁶x - tan⁶x= 1 + 3 sec²x X tan²x​...

please give step by step answer..
who will give correct I will mark them brainliest​

Answer 1

Answer:

sec⁶x - tan⁶x

(sec²x)³ - tan⁶x

(1 + tan²x)³ - tan⁶x

(1 + 3tan²x + 3tan⁴x + tan⁶x) - tan⁶x

1 + 3tan²x + 3tan⁴x

1 + 3tan²x(1 + tan²x)

1 + 3tan²xsec²x