Math, asked by syedmisbahuddin787, 9 months ago

Sec70÷cosec +sin59÷cos31

Answers

Answered by Anonymous
1

 \sec70  \div  \csc20  +  \sin59 \div  \cos31

 \sec(90 - 20)  \div  \csc(20) +  \sin(59)  \div  \cos(90 - 59)

 \sec(70)  \div  \sec(70)  +  \sin(59)  \div  \sin(59)

1 + 1

2

Hope it helps you mark as brainliest please

Answered by 18shreya2004mehta
0

Answer:

÷csc20+sin59÷cos31

\sec(90 - 20) \div \csc(20) + \sin(59) \div \cos(90 - 59)sec(90−20)÷csc(20)+sin(59)÷cos(90−59)

\sec(70) \div \sec(70) + \sin(59) \div \sin(59)sec(70)÷sec(70)+sin(59)÷sin(59)

1 + 11+1

22

Hope it helps you mark as brainliest please

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