Sec70÷cosec +sin59÷cos31
Answers
Answered by
1
Hope it helps you mark as brainliest please
Answered by
0
Answer:
÷csc20+sin59÷cos31
\sec(90 - 20) \div \csc(20) + \sin(59) \div \cos(90 - 59)sec(90−20)÷csc(20)+sin(59)÷cos(90−59)
\sec(70) \div \sec(70) + \sin(59) \div \sin(59)sec(70)÷sec(70)+sin(59)÷sin(59)
1 + 11+1
22
Hope it helps you mark as brainliest please
Similar questions