Math, asked by DagliDarshil, 11 months ago

sec70°sin20°-cos20°cosec70°​

Answers

Answered by Megarox
1

Sec70°×sin20°-cos20°xcosec70°

=1/cos70°×sin20°-cos20°x1/sin70°

=sin20°/cos°70-cos20°/sin70°

=sin20°/sin(90-70)°-cos20°/cos(90-70)°

=sin20°/sin20°-cos20°/cos20°

=1-1

=0

please mark it as the brainiest

Similar questions