Math, asked by manojlakra74, 11 months ago

Sec8x-1/sec4x-1=tan8x/tan2x

Answers

Answered by shlok91

0

Step-by-step explanation:

as 1+tan^2x=sec^2x thus tan^2x=sec^2x-1

similarly sec^8x-1=tan^8x and

sec^4x-1=tan^4x

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