Math, asked by shreedharhujaratti02, 2 months ago

SecA-1
Prove that
tanA-Sina
tanA+SinA
SecA+1​

Answers

Answered by sandy1816
2

\frac{tana - sina}{tana + sina} \\ = \frac{ \frac{sina - sinacosa}{cosa} }{ \frac{sina + sinacosa}{cosa} } \\ = \frac{sina - sinacosa}{sina + sinacosa} \\ = \frac{1 - cosa}{1 + cosa} \\ = \frac{seca - 1}{seca + 1}

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