Question

SecA-1/secA+1 = 1- cosA/1+cosA

Answer 1

Answer:

$\frac{secA-1}{secA+1}=\frac{1-cosA}{1+cosA}$

Step-by-step explanation:

$LHS = \frac{secA-1}{secA+1}$

$=\frac{\frac{1}{cosA}-1}{\frac{1}{cosA}+1}$

$=\frac{\frac{1-cosA}{cosA}}{\frac{1+cosA}{cosA}}\\=\frac{1-cosA}{1+cosA}\\=RHS$

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Answer 2

Answer:

Step-by-step explanation: