Question

seca-1/seca+1 = 1-cosa/1+cosa

Answer 1

given that sec a -1/ sec a +1 =1-cos a/ 1+ cos a
to prove LHS=RHS
now, sec a = 1/ cos a
so, (1/cos a-1) / (1/cos a+ 1)
==( 1-cos a/ cos a) / (1+cos a /cos a)
== 1-cos a / 1+cos a = RHS

Answer 2

Given Equation is sec a - 1/sec a + 1

   We know that 1/cos theta = sec theta.

= (1/cos a - 1)/(1/cos a + 1)

= (1 - cos a * 1/cos a)/(1 + cos a * 1/cos a)

= (1 - cos a/cos a)/(1 + cos a/cos a)

= 1 - cos a/1 + cos a.


Hope this helps!