Question

SecA -1 /SecA +1 = 1-CosA/1+CosA

Answer 1

=(1/cos-1)/(1/cos+1)
=(1-cos)/cos/(1+cos)/cos
=1-cos/1+cos
hence proved

Answer 2

Hey !!

So simple one ..

secA -1 /secA + 1

=> 1/cosA - 1
-------------------- •°• 1/cosA = secA
1/cosA + 1

=> 1 - cosA/cosA
-----------------------
1+cosA /cosA

=> 1 - cosA /1 + cosA RHS prooved

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Hope it helps you !!!

@Rajukumar111