SecA-1/secA+1=1-cosA/1+cosA
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Answered by
10
Answer :
Now,
L.H.S. = (secA - 1)/(secA + 1)
= (1/cosA - 1)/(1/cosA + 1), since secA = 1/cosA
= {(1 - cosA)/cosA}/{(1 + cosA)/cosA}
= (1 - cosA)/(1 + cosA)
= R.H.S. [Proved]
#MarkAsBrainliest
Now,
L.H.S. = (secA - 1)/(secA + 1)
= (1/cosA - 1)/(1/cosA + 1), since secA = 1/cosA
= {(1 - cosA)/cosA}/{(1 + cosA)/cosA}
= (1 - cosA)/(1 + cosA)
= R.H.S. [Proved]
#MarkAsBrainliest
Answered by
7
Here is the solution along with attachment
Thanks
if it helps you then please mark it as brainliest answer
Thanks
if it helps you then please mark it as brainliest answer
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