SecA-1/secA+1=1-cosA/1+cosA
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Answered by
10
Answer :
Now,
L.H.S. = (secA - 1)/(secA + 1)
= (1/cosA - 1)/(1/cosA + 1), since secA = 1/cosA
= {(1 - cosA)/cosA}/{(1 + cosA)/cosA}
= (1 - cosA)/(1 + cosA)
= R.H.S. [Proved]
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Now,
L.H.S. = (secA - 1)/(secA + 1)
= (1/cosA - 1)/(1/cosA + 1), since secA = 1/cosA
= {(1 - cosA)/cosA}/{(1 + cosA)/cosA}
= (1 - cosA)/(1 + cosA)
= R.H.S. [Proved]
#MarkAsBrainliest
Answered by
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Here is the solution along with attachment
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