(secA-1)/(secA+1)=(1-cosA)/(1+cosA)
Answers
Answered by
1
= (1 /cosA - 1)/ (1/cosA +1)
(: -secA = 1/cosA)
= (1-cosA)/cosA /(1+cosA)/cosA
= (1-cosA) /(1+cosA
(: -secA = 1/cosA)
= (1-cosA)/cosA /(1+cosA)/cosA
= (1-cosA) /(1+cosA
Answered by
2
I hope .... it's right answer
Attachments:
Similar questions