Question

secA(1-sin A) ( secA +tanA)=1​

Answer 1

=

Step-by-step explanation:

$\sec(a) .(1 - \sin( a) ).( \sec(a) + \tan(a)) = 1 \\ lhs = \sec(a) .(1 - \sin(a) )( \sec(a) + \tan(a) ) \\ (\sec(a) - \sec(a) . \sin(a) )( \sec(a) + \tan(a) ) \\ ( \sec(a) - \tan(a) )( \sec(a) + \tan(a) ) \\ \\ { \sec }^{2} (a) - { \tan}^{2} (a) \\ = 1$

hence this is proved

lhs=rhs