Math, asked by JoshuaMathew, 1 year ago

SECA(1-SINA)(SECA+TANA)=1

Answers

Answered by sandy1816

0

Step-by-step explanation:

secA(1-sinA)(secA+tanA)

=secA(1-sinA)(1+sinA/cosA)

={secA(1-sin²A)}/cosA

=(secAcos²A)/cosA

=secAcosA

=1

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