Question

secA(1-sinA)(secA+tanA)=1​

Answer 1

Answer:

Step-by-step explanation:

secA(1-sinA)(secA+tanA)

⇒1/cosA(1-sinA)(1/cosA+sinA/cosA)

we just changed all sec's and tan's to sin and cos forms for easier simplification

⇒(1-sinA/cosA)(1+sinA/cosA)

since (a+b)(a-b)= a²-b²

∴1-sin²A/cos²A

since 1-sin²A

⇒we can say that

cos²A/cos²A = 1

Hope this answers your question brother :)