secA( 1-sinA)( secA+tanA )= 1
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Answer:
sec (1- sin)(sec+tan)
(sec-sec.sin)(sec+tan)
(sec-tan)(sec+tan)
=>sec²-tan². {(a+b)(a-b)= a²- b² }
=>1 { sec²-tan²=1}
Step-by-step explanation:
hence proved
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