Math, asked by ratulbrahma2001, 6 months ago

secA (1-sinA) (secA+tanA)=1 ​

Answers

Answered by AkshatShekhar
1

Answer:

LHS = SecA(1-SinA) (SecA+TanA)

= (1/CosA) (1-SinA) (1/CosA + SinA/CosA)

= (1-SinA/CosA) (1+SinA/CosA)

= (1- SinA) (1+SinA)/ Cos²A

= 1-Sin²A/Cos²A [using (a+b)(a-b) =a²-

b²]

=Cos²A/Cos²A [using 1- Sin²A =

Cos²A]

= 1 = RHS

Answered by nandika32
0

Answer:

answer...................

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