Question

secA(1+sinA)(secA-tanA)=1​

Answer 1

Step-by-step explanation:

=> secA(1+sinA)(secA-tanA) = 1

=> 1+sinA/cosA × (1/cosA - sinA/cosA) = 1

=> 1+sinA/cosA × 1-sinA / cosA = 1

=> 1-sin²A/cos²A =1 [ (1+sinA(1-sinA)=(1-sin²A) ]

=> cos²A/ cos²A = 1 [ (1-sin²A) =cos²A ]

=> 1 = 1

proved