Question

seca(1-sina)seca+tana)​

Answer 1

Answer:

secA(1-sinA)(secA+tanA)

= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)

= (1/cos²A)(1-sinA)(1+sinA)

= (1/cos²A)(1-sin²A)

= (1/cos²A)(cos²A)

= 1

= RHS

Step-by-step explanation:

Answer 2

Step-by-step explanation:

secA( 1-sinA) ( secA+ tanA)

= ( secA - secA×sinA) ( secA+ tanA)

= ( secA - tanA) ( secA+ tanA)

= ( sec²A- tan²A)

= 1

= RHS

formula used:-

(1) secA= 1/cos A => secA. sinA.

= (1/cosA)/sinA = tanA

(2) sec²A - tan²A= 1

(3) (a-b) ( a+b)= a²-b²