Question

secA(1-sinA)(secA+tanA)​

Answer 1

Answer:

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Step-by-step explanation:

secA (1-sinA) (secA + tan A)

= (secA-sinAxsecA)(secA+tanA) =(secA-tanA) (secA+tanA) as secA-1/cosA and sinA/COSA=tanA

= (secºA-tan-A) as (a+b)(a-b)=a-b? =sec A-tan A=1 from identity. Hence proved.