Question

SecA (1-sinA) (secA+tanA) proof

Answer 1

Its seems you forgot to write, secA(1 - sinA)(secA + tanA) = 1

now,secA(1-sinA)(secA+tanA)

= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)

= (1/cos²A)(1-sinA)(1+sinA)

= (1/cos²A)(1-sin²A)

= (1/cos²A)(cos²A)

= 1

= RHS