Question

seca=13/5 show that 2 sina -3 cosa=3​

Answer 1

Answer:

Answer is not possible, Please tell me my mistake

Step-by-step explanation:

sec A =13/5

sec = h/b

so we get h =13x and b=5x

using Pythagoras theorem we get p=12x or simply 12

so your question is 2*Sin A - 3*Cos A=3

sin A = p/h = 12/13

2*sin A=2*12/13

=24/13

cos A= b/h =5/13

3*cos A=3*5/13

= 15/13

As per question 24/13 - 15/13 = 3

On taking lcm and solving LHS we get

24-15/13= 3

9/13 = 3