Question

SecA =2/√3
Find the value of
TanA/coasA + 1+sinA/tanA

Answer 1

Sec A = 2/√3 cos A = √3/2 Sin A = 1/2
tan A = 1/√3

TanA/cosA + (1+SinA)/tan A
= 2/3 + (3/2)/(1/√3)
= 2/ 3 + 3√3/2
= [4 + 9 √3]/6

Answer 2

sec A = 2/√3
sec A = sec 30°
A = 30°
therefore
tan 30°/cos 30°+ (1+sin 30°)/tan 30°
(1/√3)/(√3/2) + (1+1/2)/1/√3
1/√3 * 2/√3 + 3/2 * √3
2/3 + 3√3/2
(4+9√3)/6 is the answer