Question

(secA-2) (tan3A-1) =0, find the value of A

Answer 1

Answer:

Either secA -2=0 so SecA=2 or secA= sec 60°

A= 60°

Or, tan3A-1=0 => tan3A=1= tan 45°

3A= 45 hence A=15

A's values are 15° and 60°

Answer 2

Answer:

Either secA-2 =0 so sec A=2 or secA=sec 60°

A=60°