secA=25/7 then find sinA=??
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Answered by
3
Heya !!!
SecA = 25/7 = H/B
H = 25 and B = 7
By Pythagoras theroem,
(H)² = (B)² + (P)²
(P)² = (H)²-(B)²
(P)² = (25)² - (7)²
P = ✓576 = 24
Therefore,
SinA = P/H = 24/25
★ HOPE IT WILL HELP YOU ★
SecA = 25/7 = H/B
H = 25 and B = 7
By Pythagoras theroem,
(H)² = (B)² + (P)²
(P)² = (H)²-(B)²
(P)² = (25)² - (7)²
P = ✓576 = 24
Therefore,
SinA = P/H = 24/25
★ HOPE IT WILL HELP YOU ★
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Answered by
2
secA= 25/7
cosA= 7/25.
cos²A=49/625.
we know that cos²A + sin²A=1.
sin²A=1-cos²A
=1-49/625
=(625-49)/625
= 576/625
sinA=24/25
cosA= 7/25.
cos²A=49/625.
we know that cos²A + sin²A=1.
sin²A=1-cos²A
=1-49/625
=(625-49)/625
= 576/625
sinA=24/25
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