Question

secA+cosA=1,then sec^3A+cos^3A​

Answer 1

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Answer 2

Answer:

-2

Step-by-step explanation:

(secA+cosA)^2=1^2

secA^2+cosA^2+2cosA.secA=1

secA^2+cosA^2=-1

a^3+b^3=(a+b)(a^2+b^2-ab)

secA^3+cosA^3=(secA+cosA).(secA^2+cosA^2-secA.cosA)

=(1)(-1-1)

=