SecA+cosA=2 find sec squareA +cos square A
Answers
Answered by
0
We have secA+cosA=2
(Sq. both sides)
or,, sec^2A+cos^2A+ 2 secA.cosA=4
or, sec^2A+cos^2A+2=4
or,sec^2A+cos^2A=2
(Sq. both sides)
or,, sec^2A+cos^2A+ 2 secA.cosA=4
or, sec^2A+cos^2A+2=4
or,sec^2A+cos^2A=2
Similar questions