Question

secA + cosA =2 find sec2A+ cos2A

Answer 1

Answer:

Given -secA+cosA=2

Now find

Sec2A+cos2A

In this take common 2

so it become 2(secA+cosA) eq1

now put value so secA+cosA =2 in eq 1

2(secA+cosA)

2(2)

4 is value of sec2A+cos2A