secA+cosA=2 then secA²+secA⁴=?
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Step-by-step explanation:
secA + cosA = 2
→1/cosA + cosA =2
→(1+cos^2A)/cosA=2
→1+cos^2A = 2cosA
→cos^2A +1-2cosA =0
→(cosA-1)^2 = 0
→cosA = 1
→A =0
Thus , sec^2A + sec^4A
= sec^2 (0)+sec^4(0)
→1+1=2
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