Question

(secA - cosA)(cosecA - sinA) = sinA.cosA
please show the process of this it would help me lots!!!

Answer 1

here is the answer

thanks..

Answer 2

Answer:

( secA- cosA)(cosecA-sinA)

secA(cosecA)-cosA( cosecA)-secA(sinA)+cosA(sinA)

1/cosA( 1/sinA)-cosA(1/sinA)-1/cosA(sinA)+cosA sinA

1/( cosAsinA)-(cosA/sinA)-(sinA/cosA)+(cosAsinA)

(1-cos^2A-sin^2A+cos^2Asin^2A)/(cosAsinA)

(sin^2A-sin^2A+cos^2Asin^2A)/(cosAsinA)

(cosAsinA)^2/cosAsinA=sinA.cosA