(secA _ cosA) (cotA+ tanA) = tan A _ secA ? (please solve this question)
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Answer:
LHS=(secA-cosA) * (cotA+tanA)
=(1/cosA - cosA) * cosA/sinA + sinA/cosA)
=(1-cos^2A)/cosA * (sin^2A + cos^2A ) / sinA cosA)
={(sin^2A) /cosA}*(1/sinA cosA)
=sinA/cos^2A = (sin A/cosA)*(1/cosA)=tanA*secA=RHS
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