Question

(secA+cosA) (secA-cosA)=sin²A+tan²A

Answer 1

(Sec A+cosA)(SecA-cosA)
sec2A-cos2A
sec2A-(1-sin2A)
sec2A-1 +sin2A. {sec2A-tan2A=1}
tan2A + sin2A.

HERE IS YOUR ANS MATE!!!
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Answer 2

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