Math, asked by Girraj11, 1 year ago

secA-cosecA/secA+cosecA=tanA-1/tanA+1

Answers

Answered by Anonymous

LHS
= (1/cosA - 1/sinA) / (1/cosA + 1/sinA)
= (sinA - cosA / sinAxcosA) / (sinA + cosA / sinAxcosA)
= sinA - cosA / sinA + cosA

RHS
= (sinA/cosA - 1) / (sinA/cosA + 1)
= (sinA - cosA / cosA) (sinA + cosA / cosA)
= sinA - cosA / sinA + cosA

thereore, LHS=RHS
hence proved

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