Question

-secA × secA
- CosecA x CosecA = ?​

Answer 1

Answer:

sec2A

cosec2A is the answer

Answer 2

Answer:

$\large\boxed{\sf{{\sec}^{2}A\:\:and\:\:{\csc}^{2}A}}$

Step-by-step explanation:

sec A × sec A = ${\sec}^{2}A$

csc A × csc A = ${\csc}^{2}A$

Trignometric formule:

• ${ \sin }^{2} \alpha + { \cos }^{2} \alpha = 1$

• ${ \sec}^{2} \alpha = 1 + { \tan}^{2} \alpha$

• ${ \csc}^{2} \alpha = 1 + { \cot }^{2} \alpha$

• $\sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha )$

• $\cos(2 \alpha ) = { \cos}^{2} \alpha - { \sin}^{2} \alpha$