Math, asked by sutapapayel, 10 months ago

(secA-secB)/(tanA+tanB) = (tanA-tanB)/(secA+secB)

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Answered by vijaydk24

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Prove: (seca-secb)/(tana+ tanb)=(tan-tanb)/(seca+secb). Ask for details; Follow; Report. by Kamrulhaque

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