Math, asked by ravibi1971, 10 months ago

secA/sinA-sinA/cosA =cotA​

Answers

Answered by devrishabh3387
4

Answer:

Step-by-step explanation:

SecA/SinA-SinA/CosA=cotA

1/cosA/SinA-SinA/CosA=CotA

1/SinACosA-sinA/cosA=cotA

cosA-sin²AcosA/sinAcos²A=cotA

cosA(1-Sin²A)/SinACos²A=cotA

Cos³A/SinACos²A=CotA

CosA/SinA=CotA

CotA=CotA...

Hence,LHS=RHS

Answered by khushichoudhary30
3

Step-by-step explanation:

secA/sinA - sinA/cosA= cotA

L.H.S.

secA/SinA - sinA/cosA

1/cosA/sinA - sinA/cosA

1/sinAcosA - sinA/cosA

cosA - sin²AcosA/sinAcos²A

cosA(1-sin²A) / sinAcos²A

cosA (Cos²A)/sinAcos²A

cos³A / sinAcos²A

cosA/sinA

So,

L.H.S. = R.H.S.

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