Question

secA + tanA= 1/2 find secA- tanA​

Answer 1

If SecA+tanA= 1/2, what is the value of SecA=tanA?

ANSWER TO YOUR QUESTION:

I suppose you mean Sec A - Tan A.

Sec A + Tan A = 1/2 —————- Eq. 1

Sec A - Tan A = m ————— Eq. 2

Add (1) and (2)

2Sec A = m + 1/2 = (2m+1)/4

Subtract (1) from (2)

2Tan A = m - 1/2 = (2m-1)/4

Identity: 1 + Tan^2A = Sec^2A

1 + [(2m-1)/4]^2 = [(2m+1)/4]^2

1 + [4m^2 + 1 - 4m]/16 = [4m^2 + 1 + 4m]/16

16 + 4m^2 - 4m + 1 = 4m^2 + 4m + 1 —————-:: 16 will cancel

16 -4m - 4m = 0

-8m = -16 —————-:: -ve signs will cancel

m = 2

Hence, Sec A - Tan A = 2.

Answer 2

Answer:

(seca - tana) = 2

Step-by-step explanation:

$we \: know \: that \: \\ {sec}^{2} a - {tan}^{2} a = 1 \\ (seca + tana ) (seca - tana) = 1 \\ \frac{1}{2} \times (seca - tana) = 1 \\ (seca - tana) = 1 \times 2 \\ (seca - tana) = 2$