Math, asked by varunkumar86, 1 year ago

(secA-TanA)=1/3, then find cotA​

Answers

Answered by harshitagarwal624
0

 \sec(a)  =  \frac{1}{3}  +  \tan(a) \\ squaring \: both \: the \: sides \\  { \sec(a) }^{2}  =  \frac{1}{9}  +  { \tan(a) }^{2}  +  \frac{2}{3} \tan(a)  \\  { \sec(a) }^{2}  -  { \tan(a) }^{2}  =  \frac{1}{9}  +  \frac{2}{3} \tan(a)  \\   \frac{ - 2}{3} tan(a)   =  \frac{1}{9}  \\  \tan(a)  =  \frac{1}{9}  \times  \frac{3}{ - 2}  \\ tan(a) =  \frac{1}{ - 6}  \\ so \\  \cot(a)  =  - 6

#hope it help uh.

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Answered by Kalpanadasam
0

Answer:

Step-by-step explanation:secA-tanA=1/3

SecA=1/3+tanA

Squaring on both sides

Sec2A=1/9+tan2A+2/3tanA

Sec2A-tan2A=1/9+2/3tanA

1=1/9+2/3tanA

1-1/9=2/3tanA

8/9=2/3tanA

8/9*2/3=tanA

4/3=tanA

CotA=3/4

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