Question

(secA + tana - 1)(secA -tan A + 1) - 2 tanA=​

Answer 1

Step-by-step explanation:

{(secA+tanA)-1}{(secA-tanA)+1}-2tanA

=(secA+tanA)(secA-tanA)+(secA+tanA) -(secA-tanA)-1-2tanA

=(sec²A-tan²A)+secA+tanA-secA+tanA-1 -2tanA

=1+2tanA-1-2tanA

=0