Math, asked by manasp280191, 4 months ago

secA + tanA=
1/
secA - tan A

Answers

Answered by priyasha366
1

Step-by-step explanation:

multiply (secA - tan A ) with numerator and denominator

(secA + tanA ) * (secA - tan A) / 1*(secA - tan A)

(sec^2 - tan^2 )/ secA - tan A   {tan^2 +1= sec^2}  {sec^2 -tan^2 =1}

1/secA - tanA

LHS = RHS

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